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find resistance r1 and r2 if only vin and out is given?

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How to find r1 and r2 values if only vout and vin is given. i have tried all voltage divider formulas but none of them work. I think it cant be found.Screenshot_1.png
 
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Harald Kapp

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3.1415 Ω and 2.7182 Ω

In all honesty: How are we to know which are R1 and R1 without a circuit diagram? Upload a schematic diagram clearly indicating R1, R2, Vin and Vout, then we will be able to help.
 
If the circuit does not have to deliver any significant current (for example, it is driving only a volt meter), then there are an infinite number of resistor value combinations that will do what you want. If you stick to only resistor values you can buy, then there are approximately 331,000 1% tolerance resistor combinations.

ak
 

davenn

Moderator
If the circuit does not have to deliver any significant current (for example, it is driving only a volt meter), then there are an infinite number of resistor value combinations that will do what you want. If you stick to only resistor values you can buy, then there are approximately 331,000 1% tolerance resistor combinations.

ak


That's seriously overcomplicating the discussion ;)
 
12V is reduced to 9V so one third of the voltage is across R1 and two thirds across R2.
Chose a resistor (any value) for R1 and then R2 will be double this.
[mod edit: solution removed]
 
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Harald Kapp

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Chose a resistor (any value) for R1 and then R2 will be double this.
This is probably the direction the original assignment was directed at. Give the required ratio of R1/R2 or an equation for R1=f(R2) (or vice versa).

We have here one equation (voltage divider) but 2 degrees of freedom (R1, R2). This cannot be evaluated without making assumptions (e.g. about the value of either R1 or R2) that are not warranted by the task description (as far as we know it).
 

hevans1944

Hop - AC8NS
I like @davenn's post #3, to which the OP has not bothered to respond. All remaining comments in this thread (including mine, which was deleted for revealing too much) are just noise IMHO until @Malik Nouman responds to Dave's questions. Unfortunately, Malik appears to be just another "drive-by poster" looking for a quick answer to a homework problem, rather than a participant in a learning experience. What a FWOT!
 
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