clipping circuit

[bhuvanesh]

First i admit i am weak on basics.See the image, i am measuring the voltage across the diode.Actually it only passes positive wave,but it also passing negative value.what i misunderstood here.

 

[BobK]

Look at where your oscilloscope leads are. They are connected to ground and the sine output of the signal generator, of course you will see a sine wave.

Put a resistor (1K) between the cathode of the diode and ground, and move the scope lead from the anode to the cathode, and see if that changes anything. The scope leads should be on both sides of the resistor.

Bob

 

[bhuvanesh]

thanks i got that,even though the diode is shorted it have small resistance that make the sine wave appear in output ,right

 

[Laplace]

You are using a simulation program, so the question is what assumptions the program makes to simulate the real world? Suppose you replace the diode with a resistor, then reduce the resistance in a series of steps (10Ω, 1Ω. 0.1Ω, 0.01Ω, ....) to see how close you can get to a short circuit before the scope shows some effect. In the simulation, how much current can the signal source provide? Is it programmed as an ideal source?