Finally, I managed to key the relay, following your tips about pin 16.
As there was too few voltage across it, I made this reasoning: the near positive terminal of 9V battery has about 7.6V (I replaced the old battery with a new one), enough to give sufficient power to pin 16. So I tried to make a bridge between the positive terminal and the track in front of that terminal (which I scratched a bit to uncover the foil path) that brings to pin 16.
It seems that now the AC crosses the relay, arriving at L1 and, on the front side PCB track, stopping at C5 (the first of the 2 capacitors in series), while continuing its route on the back side PCB track in 2 directions: up to the rectifying diode (D9) and down to C, the common terminal (bottom left of the PCB).
So, starting to measure alternating voltage values from the beginning, I updated the photo. At the relay I checked both AV and DV. All contacts have a voltage value, except for pin 6. Is it normal? If not, I guess it's not due to the relay itself because I replaced it after the displays' issue.
I've always thought that the whole problem was born after a short circuit happened in the relay area, probably between pin 8 and another one (perhaps the companion 9). Well, if this happened, 28V arrived everywhere (or almost but surely at the COB) causing a "little" problem.
But now let's continue with the AC route. As I said, L1, after the relay, and C5. There, it stops but I suppose that the aim of C5 and C6 in series is just that.
So, D9 comes and on its cathode we have 36.3Vdc, nearly the same voltage in R3 and the close left pin of R5 (whose connection to R3 I now show with a greenish-blue mark on the photo). At that point great job for R5: voltage drops from 36V to about 12V. From there to the close D10 and ZD1 (which is in a short condition) and then down to the "operational area" (the hole near Q19), supplying the necessary voltage to the various transistors. But I'd like to get back later on this point as I wish to know your opinion about a possible solution involving the "operational area".
About ZD1. Considering the voltage value before the zener (approximately 12V) and the path after it, what are the right values (in terms of W and V) that ZD1 could have in my PCB?
Now, let's go straight to the IC marked "C2ZD". I have found the datasheet of a series of voltage regulators (see this link:
http://www.sii-ic.com/en/semicon/datasheets/power-management-ic/voltage-regulator-ldo/s-812c/). There is no final "D" but only the other 3 letters (only a chinese website shows all the letters but there is no datasheet available). If it is the same component as mine (despite that "D"), is that working efficiently? I only know that before the COB, R1 has 5.1V and the crystal has 1.9V and 4.5V on its pins. Then after the COB, all the displays' pins have about 1.7V but nothing appears on the LCD, as the last time, no matter the voltage arriving at the COB.
The C2ZD is just a voltage regulator: this time output 8.1V from 11.9V, while the last time 3.73V from 7.25V (due to the smaller power of the 9V battery). By the way, the last time crystal's values were 0.43V and 1.56V with no voltage across displays' pins.
Earlier I mentioned the "operational area" because I got an idea but I don't know if it's feasible. If you look at the last photo, I drew a red rectangle on the right, a hypothetical component or device whose name and possible existence are unknown to me. Before, there are 12-13V coming. This voltage should get into this device which would provide 4 different lines as output, each sequentially activated for an amount of time.
So, 12-13V arrive but firstly only the line 1 gets the current for 1 hour (just an example of time). At the end, it's the turn of the line 2 and so on until the line 4.
I would connect each output line (using insulated wires) to a small piece of track after the transistor emitter because it's there that the DC should be, flowing then down until the terminal contact. In this way, I would bypass the COB signal to the transistor base. I simply would not need it. And I would successfully solve the whole problem, activating each sprinkle line simply by connecting the 9V battery (to key the relay) and the 24VAC (then reduced to 12-13VDC).
It looks like a signal splitter combined with a timer. I'm afraid it doesn't exist or, at least, it would cost too much.
Otherwise, is there a way to apply the logics I've just explained?
I just need a sequential start of the sprinkle lines for 1 hour each, that's all. If we can modify the final part of the circuit to accomplish this need, we definitely solve the problem. What do you think? Could we take advantage of the power arriving at the operational area to sequentially activate the 4 lines?
Here are the electrical specifications regarding the station output power:
- 24 VAC
- 6 VA (0.25 amps) per station maximum
- 6 VA (0.25 amps) pump start/master valve
- 12 VA (0.50 amps) total load
Following are the 3 photos. Unfortunately I didn't take the chance to get a shot of the PCB in the sunlight but I managed to take a better photo of the bottom left quadrant, as you suggested. I hope it will be fine for a quick understanding of the operational area.