The bigger picture? I could tell you but I'd have to track you down and kill you!
Seriously, if this was true you would have more resources available to you than a forum on the Internet.
The purpose of the setup I've described over many posts is to be able to fire high-power transients at a test load and monitor the response. Whilst this thread is specific to the power source, some of the other threads relate to the control of this source via an IGBT-based H-bridge that can pulse the power, short it and reverse it. The onboard micro-controller allows us to do this is various sequenced fashions. By doing this we can understand more about our test loads.
OK, so you have a bank of 12 x 12V Lead acid batteries providing a nominal 150VDC rail to some unspecified load.
Presumably the series resistor is not required for the load's normal operation.
The rest of your magic is applying transient voltages to the load, and for this you have a current limit on your power supply to partially isolate the transient source from the battery.
Am I right so far?
What you want to be able to do is superimpose these transients (being spikes in either direction) onto the power supply without them being absorbed by the battery (you're testing the load not the battery).
I think you have suggested that the load requires 40A at 150V, although I am not certain if you were referring to the short circuit current limit or the static load there.
The problem you have (I think) is that the power supply has a very low impedance and your attempts at introducing transients in parallel with the batteries results in the transient being mostly absorbed by the batteries rather than being delivered to the load.
If this is the case, then you need to look at some method of adding the transient voltage in series with the battery rather than in parallel with it, or by isolating the battery from the transient using a diode.
The attached schematic shows what I mean. In all cases I show a capacitor charged by a battery and then switched so as to cause a transient. I show a capacitor because in cases I've seen a transient is measured by both the peak voltage and the energy -- a capacitor easily qualifies for this, but you may choose an alternate arrangement. Also no resistors to limit the charge (or discharge) current are shown.
The capacitor across the load delivers positive transients -- they are isolated from the power supply by the diode, so they are delivered to the load. The battery charging the capacitor must have a voltage equal to the power supply voltage PLUS the transient voltage (e.g. for a 150V PSU and a required 50V transient, you would require a 200V source here)
The capacitor in parallel with the diode creates negative transients. Being in series with the main power supply means that the transient voltage is applied to the load. Any voltage that is applied to the capacitor will create a transient. If the voltage is less than the PSU, the transient will not go to ground. If the voltage is > PSU you will get negative going transients.
It is unlikely that you would use a switch, or batteries, or possibly even capacitors, but this method of applying transients will not cause the current issues *I think* you're having with the power supply.
I could, however, have it all wrong