A/D impedance PIC connected to RC circuit

[Rajinder]

Hi all,
I have a RC circuit in parallel 330K and 1uF.
This is going to be connected to an A/D input of a PIC. The PIC is a 16LF1936, which says the impedance is 10K source.

1. How do i calculate the impedance of the RC circuit? I think it is Z=squareroot of RxR + Xc x XC.
XC is the reactance of the capacitor. 1/2x3.142xfreqxcapacitor.
2. For capacitive reactance, what should the frequency be? Would it be at DC i.e. 0Hz. If that is the case the RC impedance is only 390K. Is that correct?
3. If the source impedance of the PIC is 10K, then the RC impedance needs to be greater than this or the signal is reduced.

Does all this seem correct?
Thanks in advance.

 

[BobK]

Show us how it is connected.

Bob

 

[hevans1944]

Does all this seem correct?

As @BobK (quietly) said: SHOW US HOW IT IS CONNECTED! (shouting and emphasis mine because original poster doesn't appear to be paying attention)

And to answer your question #4: No, nothing about your post appears to be correct. Capacitive reactance is not defined at DC, which by definition is zero frequency, because division by zero is not allowed! So, your "calculations" are not only wrong but irrelevant.

Statement #3 is totally wrong: the source impedance to the PIC's ADC should be as small as possible, certainly less the 10 kΩ, to avoid attenuating the signal. The source impedance along with the ADC input impedance form a voltage divider, with the attenuated divider output appearing as the input to the ADC. When driving a PIC ADC (or any other ADC), typically a low-impedance source such as an operational amplifier serves this purpose. Also, whatever attenuation of the input signal does occur can be compensated by a small gain in the op-amp circuit, or "calibrated out" of the digital conversion from the ADC.

So, please show us your RC circuit and how you plan to connect it to the PIC A/D converter input.

 

[Harald Kapp]

#1: See e.g. here.
#2: Your question doesn't make sense: the reactance of a capacitor is frequency dependent, therefore you need to consider teh range of relevant frequencies. Your circuit will have a different impedance at each frequency, including DC.
#3: Much greater, see Hop's explanation in post #3
#4: No.

 

[Rajinder]

Hi, sorry but i cant seem to.upload files. Keep getting errors. I will upload tonight from my PC.
Thanks

 

[hevans1944]

Hi, sorry but i cant seem to.upload files. Keep getting errors. I will upload tonight from my PC.
Thanks

I had the same problem the other day. Kept getting an error message saying it couldn't upload my image file. My eventual solution was to load the image in Microsoft Paint, size it to 1024 x 768 pixels and then save the re-sized image under a different file name. The new image file uploaded just fine and I didn't notice the decrease in image resolution. The software for uploading an image on this forum doesn't tell you why it failed.

 

[Harald Kapp]

Despite was is often said: size matters. I don't know where the limit is here, but reducing file size usually helps.